import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String[] args) {
final String regex = "\\s*@\\S+";
final String string = "@elonmusk @CoinDesk @Aoyon_A @realDannyNelson LIST BINANCE #squidgame $10000 ,#Marble $10000 #bitcoin $100000 #ETH 10000, #BNB $5000.@squid_holders@SQUID_DAO_GAME@DumbleSherrill #Squidgame : 0x87230146e138d3f296a9a77e497a2a83012e9bc5#Squidgame marble: 0x9531c509a24ceec710529645fc347341ff9f15eaGo to the moon\n"
+ "Some @elonmusk,@elonmusks mention,@elonmusk. See lala@llalall.com.";
final String subst = "";
final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
final Matcher matcher = pattern.matcher(string);
// The substituted value will be contained in the result variable
final String result = matcher.replaceAll(subst);
System.out.println("Substitution result: " + result);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Java, please visit: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html