re = /^\s*(?:(?:\S\s?)*\s+){2}(?:L\d+:\s*)?| +(?= )/m
str = '1FC8 0801 000A BTst.B #$A, D1
1FCC 6608 BNE.B L315
1FCE 0240 00FF And #$FF, D0
1FD2 43F8 0400 Lea.L (DispatchTab), A1
1FD6 E548 L315: LsL #$2, D0
1FD8 2388 0000 Move.L A0, $0(A1,D0.W)
1FDC 7000 MoveQ.L #$0, D0
1FDE 4E75 Rts
1FE0 6102 L316: Bsr.B P42
1FE2 60F2 Bra.B L315
P42:
1FE4 0240 01FF And #$1FF, D0
1FE8 43F8 0C00 Lea.L (ToolDispTable), A1
1FEC 0C40 0057 Cmp #$57, D0
1FF0 6212 BHI.B L318
1FF2 670C BEQ.B L317
1FF4 0C40 004F Cmp #$4F, D0
1FF8 6306 BLS.B L317
1FFA 0C40 0054 Cmp #$54, D0
1FFE 6604 BNE.B L318
2000 43F8 0400 L317: Lea.L (DispatchTab), A1
2004 4E75 L318: Rts
2006 61DC L319: Bsr.B P42
2008 601C Bra.B L320
P_tGetTrapAddress:
200A 0801 0009 BTst.B #$9, D1
200E 67F6 BEQ.B L319
2010 0240 01FF And #$1FF, D0
2014 43F8 0C00 Lea.L (ToolDispTable), A1
2018 0801 000A BTst.B #$A, D1
201C 6608 BNE.B L320
201E 0240 00FF And #$FF, D0
2022 43F8 0400 Lea.L (DispatchTab), A1
2026 E548 L320: LsL #$2, D0
2028 2071 0000 Move.L $0(A1,D0.W), A0
202C 7000 MoveQ.L #$0, D0
202E 4E75 Rts'
subst = ''
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html