import Foundation
let pattern = #"^(?=\d{2}([-\/])\d{2}(?:\1)\d{4})(?:((?:(?:0[13578]|1[02])[-\/](?:0[1-9]|[1-2]\d|3[01])|(?:0[469]|11)[-\/](?:0[1-9]|[1-2]\d|30)|02[-\/](?:0[1-9]|[1-2]\d))[-\/])(?:19\d{2}|200[0-4])|(?!09[-\/](?:19|2|3)|1)(?-1)2005)$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
MATCH:
09/18/2005
08/05/2004
01/01/2000
01/02/1934
09-18-2005
12/13/2000
12/31/2000
12-31-2000
11/30/2000
02/28/2002
02/29/2002
04-30-2005
06/04/1987
10/23/1999
02/25/2004
NO MATCH:
01/01/2006
09/19/2005
09/25/2005
09-19-2005
09-18/2005
09/18-2005
10/20/2005
08/34/2004
01/00/2000
00/01/2000
001/01/2000
01/001/2000
13/14/2000
12/32/2000
11/31/2000
11/30/ 2000
01/02/1834
02/30/2002
04-31-2005
09/18/2023
06/23/2008
04/03/2026
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression