re = /^[^%\n]*(?:%(?!3F)[^%\n]*)*/m
str = 'https%3A%2F%2Fwww.facebook.com%2F
https%3A%2F%2Fwww.facebook.com%2F%3Futm_source'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html