import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String[] args) {
final String regex = ".*(?<=GET )([^ ]*).*";
final String string = "00.00.00.00 - - [23/Mar/2020:16:23:04 +0000] \"GET /foo/bar/uri.js?id=123 HTTP/1.1\" 200 19165 \"https://nginx.com/foo/bar\" \"Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_3) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/80.0.3987.132 Safari/537.36\" \"00.00.00.00\" 0.000\n\n"
+ "00.00.00.00 - - [23/Mar/2020:16:23:04 +0000] \"GET /foo/bar/uri HTTP/1.1\" 200 19165 \"https://nginx.com/foo/bar\" \"Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_3) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/80.0.3987.132 Safari/537.36\" \"00.00.00.00\" 0.000\n\n"
+ "00.00.00.00 - - [23/Mar/2020:16:23:04 +0000] \"GET /foo/bar/uri.png HTTP/1.1\" 200 19165 \"https://nginx.com/foo/bar\" \"Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_3) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/80.0.3987.132 Safari/537.36\" \"00.00.00.00\" 0.000";
final String subst = "$1";
final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
final Matcher matcher = pattern.matcher(string);
// The substituted value will be contained in the result variable
final String result = matcher.replaceAll(subst);
System.out.println("Substitution result: " + result);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Java, please visit: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html