import Foundation
let pattern = #"^(?=[^P]*(?:ParNew|P.*ParNew|PSYoungGen|DefNew)).*?(?P<ParNew_before_1>\d+)K->(?P<ParNew_after_1>\d+)K\((?P<young_heap_size>\d+)K\), (?P<par_new_duration>\d+\.\d+) secs\] (?P<ParNew_before_2>\d+)K\->(?P<ParNew_after_2>\d+)K\((?P<total_heap_size>\d+)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
146372.273: [GC146372.274: [ParNew: 378633K->88155K(419456K), 0.0313803 secs] 9893391K->9602913K(12478080K), 0.0320299 secs] [Times: user=0.32 sys=0.01, real=0.03 secs]
2017-05-12T10:35:46.076+0000: 2.799: [GC2017-05-12T10:35:46.076+0000: 2.800: [ParNew: 409024K->51072K(460096K), 0.3273966 secs] 409024K->121051K(2046080K), 0.3275292 secs] [Times: user=0.31 sys=0.07, real=0.33 secs]
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression