re = /(?m)^(?>(?>\d+([ \t]|$)(?=.*\n(\2?+\d+\1)))+\n(?=\2$))+.*/m
str = '0 4 8 4
9 6 5 7
9 5 5 1'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html