re = /^X\.(?:[3-9]|1[0-3])(?!\d)/m
str = 'X.2
X.3word
X.4w
X.5w
X.6w
X.7w
X.8w
X.9w
X.10w
X.11w
X.12w
X.13w
X.14'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html