re = /((\d){21}(,)?){1,4}((\d){21})+/
str = '111111111111111111111
111111111111111111111,
111111111111111111111,111111111111111111111
111111111111111111111,111111111111111111111,111111111111111111111x
111111111111111111111,111111111111111111111000
111111111111111111111,,111111111111111111111
111111111111111111111,111111111111111111111,111111111111111111111,
111111111111111111111,111111111111111111111,111111111111111111111,111111111111111111111,111111111111111111111
111111111111111111111,111111111111111111111,111111111111111111111,111111111111111111111,111111111111111111111,111111111111111111111'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html