re = /([A-Z ]+)\n--(.*?)--\n(.*?)\n\n/m
str = 'Washington, DC November 27, 2019
USDA Truck Rate Report
WA_FV190
FIRST PRICE RANGE FOR WEEK OF NOVEMBER 20-26 2019
SECOND PRICE MOSTLY FOR TUESDAY NOVEMBER 26 2019
PERCENTAGE OF CHANGE FROM TUESDAY NOVEMBER 19 2019 SHOWN IN ().
In areas where rates are based on package rates, per-load rates were
derived by multiplying the package rate by the number of packages in
the most usual load in a 48-53 foot trailer.
CENTRAL AND WESTERN ARIZONA
-- LETTUCE, BROCCOLI, CAULIFLOWER, ROMAINE AND LEAF LETTUCE SLIGHT SHORTAGE
--
ATLANTA 5100 5500
BALTIMORE 6300 6600
BOSTON 7000 7300
CHICAGO 4500 4900
DALLAS 3400 3800
MIAMI 6400 6700
NEW YORK 6600 6900
PHILADELPHIA 6400 6700
2019 2018
NOV 17-23 NOV 18-24
U.S. 25,701 22,956
IMPORTS 13,653 15,699
------------ --------------
sum 39,354 38,655'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html