import Foundation
let pattern = #"\d{1}\s{16}(\d{4})(\d{9})\s{7}[A-Z\s]{25}(\d{10})[A-Za-z\s]{32}\s{3}\d{1}\d{2}[A-Za-z\s\d]{10}(\d{6})(\d{13})\d{3}\s{5}\d{2}[A-Z]{1}(\d{6})\d{2}\s{2}\d{13}\s{45}\d{2}(\d{14})([A-Z\s]{35})\s{5}([A-Z0-9\s]{40})\s{7}"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"1 0839854268058 0002611724 101312366 0712170000000020887041 08A24111718 1000000000100 0100001065768010JULIO CEZAR OZORIO DA SILVA BL S AP 202 0200194800000ALVORADA RS 000002"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression