re = /^(\d)x(\d+)\)/m
str = 'A(1x5)BC
ADVENT
A(1x5)BC
(3x3)XYZ
A(2x2)BCD(2x2)EFG
(6x1)(1x3)A
X(8x2)(3x3)ABCY
1x5)BC'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html