import Foundation
let pattern = #"\b\d{6}(?:\d{3})?\b"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
ID 123 - it should not meet the regext as it is 3 digits
ID 1234 - it should not meet the regext as it is 4 digits
ID 12345 - it should not meet the regext as it is 5 digits
ID 123456 - it should meet the regex it is 6 digits <==========
ID 1234567 - it should not meet the regext as it is 7 digits
ID 12345678 - it should not meet the regext as it is 8 digits
ID 123456789 - it should meet the regext as it is 9 digits <==========
ID 1234567890 - it should not meet the regext as it is 10 digits
ID 12345678901 - it should not meet the regext as it is 11 digits
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression