import Foundation
let pattern = #"(?-s)(^.+\R?)\b\d{2}\.\d{2}\b%(?=((?:\R^.+){2}))"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
tttttttttttyyyyyyyyyyyyyy 28758.gif: 100.00%
tttttttttttyyyyyyyyyyyyyy 28759.gif: 98.92%
tttttttttttyyyyyyyyyyyyyy 28760.gif: 100.00%
tttttttttttyyyyyyyyyyyyyy 28761.gif: 98.54%
tttttttttttyyyyyyyyyyyyyy 28762.gif: 100.00%
tttttttttttyyyyyyyyyyyyyy 28763.gif: 98.85%
tttttttttttyyyyyyyyyyyyyy 28764.gif: 100.00%
tttttttttttyyyyyyyyyyyyyy 28765.gif: 99.91%
tttttttttttyyyyyyyyyyyyyy 28766.gif: 100.00%
tttttttttttyyyyyyyyyyyyyy 28767.gif: 100.00%
tttttttttttyyyyyyyyyyyyyy 28768.gif: 100.00%
tttttttttttyyyyyyyyyyyyyy 28834.gif: 100.00%
tttttttttttyyyyyyyyyyyyyy 28835.gif: 100.00%
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression