import re
regex = re.compile(r"^(?![^?\n]*\?).*good\s+answer", flags=re.MULTILINE)
test_str = ("Here are the strings I want to detect:\n"
"--------------------------------------\n"
"That a very good answer!\n"
"(Other than that, this is a really good answer and I've upvoted it.)\n"
"good answer dvdf!\n"
"dsds good answer cfds\n"
"It is a good answer, but I feel it played into the OP's hands really. You said what they wanted to hear - that they shouldn't freely share the information because it is like a child cheating on their homework. It is contrary to the spirit of this site, and I'm not sure that charging a colleague money to learn something work-based from you won't get the OP into trouble with their employer. Imagine if a doctor asked to confer with a fellow doctor in order to help a patient, and they charged each other for the information they shared. They'd be dismissed.\n\n"
"Here are the one I don't want to detect\n"
"-----------------------------------------\n"
"Thanks for this good answer! (I upvoted it) However, I still don't understand why I shouldn't mention that I believe whatever? What's the problem with that...\n"
"cxvd good answer? zedfs\n"
"ezdds? good answer dsf dsf\n"
"sdsd? dsfdsf? good answer!\n"
"Hi, the question is \"How to tell blabla when X is my good friend\", would you mind be a little more detail about how OP should do that when OP still want to be friend with both parties? Also, please take some time to read \"How do I write a good answer\n"
"As a side note, here is a link to \"How do I write a good answer?\n"
"Hi, this sound like a good answer to me, I just have one question though: Where you in a similar situation before where you successfully used this technic? In here it's better to back-up your answer with personal experience (here is a guide to How to write a good answer if you need it)")
matches = regex.finditer(test_str)
for match_num, match in enumerate(matches, start=1):
print(f"Match {match_num} was found at {match.start()}-{match.end()}: {match.group()}")
for group_num, group in enumerate(match.groups(), start=1):
print(f"Group {group_num} found at {match.start(group_num)}-{match.end(group_num)}: {group}")
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html