using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @"(?:\),\(\d{1,4},|,\d{10},)(*SKIP)(?!)|.";
string substitution = @"";
string input = @"Text ),(1234, and more ,0123456789, here
),(39,' ',1,'01761472100','@','9 ','20',1237213277,0,1237215419,''),(40,' ',3,'01445731203','@',' ','-','22 2','210410//816',1237225423,0,1484651768,''),(4270,' /";
Regex regex = new Regex(pattern);
string result = regex.Replace(input, substitution);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for C#, please visit: https://msdn.microsoft.com/en-us/library/system.text.regularexpressions.regex(v=vs.110).aspx