re = /^(\d+\s?(years|year|months|month|weeks|week|days|day|hours|hour|minutes|minute|min|mins|seconds|second|sec|secs|y|M|w|d|h|m|s)\s?)+$/i
str = '1y 5M 3w 5d 23h 59m 50s'
# Print the match result
str.match(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html