import Foundation
let pattern = #"(?:<(?:(?:(?:(script|style|object|embed|applet|noframes|noscript|noembed)(?:\s+(?>"[\S\s]*?"|'[\S\s]*?'|(?:(?!/>)[^>])?)+)?\s*>)[\S\s]*?</\1\s*(?=>))|(?:/?[\w:]+\s*/?)|(?:[\w:]+\s+(?:"[\S\s]*?"|'[\S\s]*?'|[^>]?)+\s*/?)|\?[\S\s]*?\?|(?:!(?:(?:DOCTYPE[\S\s]*?)|(?:\[CDATA\[[\S\s]*?\]\])|(?:--[\S\s]*?--)|(?:ATTLIST[\S\s]*?)|(?:ENTITY[\S\s]*?)|(?:ELEMENT[\S\s]*?))))>(*SKIP)(*FAIL)|[<>"&'])"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
Lorem ipsum dolor sit amet, "consetetur" sadipscing elitr.
<ul>
<li>At vero eos et accusam et justo</li
<li>Stet clita "kasd" gubergren</li>
</ul>
<a href="https://www.google.com/" target="_blank">https://www.google.com/</a>
"At vero eos et accusam et justo duo dolores et ea rebum. , no sea takimata sanctus est Lorem ipsum dolor sit amet."
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression