import Foundation
let pattern = #"(?:(?:192\.)(?:(?:168\.)(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?\.)(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)))|(?:(?:10\.)(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){2}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?))|(?:(?:172\.)(?:(?:1[6-9]|2[0-9]|3[0-1])\.)(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.)(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?))"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
10.10.1.1
172.16.11.5
172.31.255.255
172.30.12.11
172.19.12.22
10.1.12.3
10.0.0.0
192.168.1.1
192.168.12.3
11.156.11.1
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression