import Foundation
let pattern = #"\W\n?(((1|2)[0-9]|3[0-1]|0?[1-9])\/(0?[1-9]|1[0-2])\/((19|20)?[0-9]{2})|((1|2)[0-9]|3[0-1]|0?[1-9])\-(0?[1-9]|1[0-2])\-((19|20)?[0-9]{2})|((19|20)?[0-9]{2})\/((1|2)[0-9]|3[0-1]|0?[1-9])\/(0?[1-9]|1[0-2])|((19|20)?[0-9]{2})\-((1|2)[0-9]|3[0-1]|0?[1-9])\-(0?[1-9]|1[0-2]))\W\n?"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
12-01-2019
01/10/2019
1-12-1901
04/04/2019
2000-02-12
2000/10/12
1800-1-9
1976/3/1
32/01/3019
9/1/30
5542-21-54
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression