use strict;
my $str = '2015	64	Fiat 500 S Hatchback 1.2 Manual Petrol	Silver White	13000	£7,495
2012	12	Fiat 500 Lounge Hatchback 1.2 Manual Petrol	White	9000	£5,495
2014	14	Fiat Panda Pop Hatchback 1.2 Manual Petrol	White	30000	£4,695
2009	09	Fiat 500 Pop Hatchback 1.2 Manual Petrol	Yellow	31000	£4,295';
my $regex = qr/\d+\K\d{3}(?=\h£)/p;
my $subst = ',$0';
my $result = $str =~ s/$regex/$subst/rg;
print "The result of the substitution is' $result\n";
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Perl, please visit: http://perldoc.perl.org/perlre.html