import re
regex = re.compile(r"[^[:print:]]\[[^a-zA-Z]*[a-zA-Z]", flags=re.MULTILINE)
test_str = ("[BEGIN TYPESCRIPT]\n"
"[H[JLinux dcim-mao 4.19.0-20-cloud-amd64 #1 SMP Debian 4.19.235-1 (2022-03-17) x86_64\n\n"
"The programs included with the Debian GNU/Linux system are free software;\n"
"the exact distribution terms for each program are described in the\n"
"individual files in /usr/share/doc/*/copyright.\n\n"
"Debian GNU/Linux comes with ABSOLUTELY NO WARRANTY, to the extent\n"
"permitted by applicable law.\n"
"Last login: Mon Jul 10 08:00:55 2023 from 172.17.0.2\n\n"
"[?2004hroot@dcim-mao:~# cd\n"
"[?2004l\n"
"[?2004hroot@dcim-mao:~# ls\n"
"[?2004l\n"
"[?2004hroot@dcim-mao:~# cd /\n"
"[?2004l\n"
"[?2004hroot@dcim-mao:/# ls\n"
"[?2004l\n"
"app etc media public srv usr\n"
"bin home mnt root supervisor.conf var\n"
"boot lib opt run sys\n"
"dev lib64 proc sbin tmp\n"
"[?2004hroot@dcim-mao:/# \n"
"[END TYPESCRIPT]")
matches = regex.finditer(test_str)
for match_num, match in enumerate(matches, start=1):
print(f"Match {match_num} was found at {match.start()}-{match.end()}: {match.group()}")
for group_num, group in enumerate(match.groups(), start=1):
print(f"Group {group_num} found at {match.start(group_num)}-{match.end(group_num)}: {group}")
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html