import Foundation
let pattern = ##"(?=(?:^(?:\+?1\s*(?:[.-]\s*)?)?(?!(?:(?:.*\(.*)|(?:.*\).*)))(?:[2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9]))|(?:.*\((?:[2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9])\).*))(?:\+?1\s*(?:[.-]\s*)?)?(?:\(?([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9])\)?)\s*(?:[.-]\s*)?([2-9]1[02-9]|[2-9][02-9]1|[2-9][02-9]{2})\s*(?:[.-]\s*)?([0-9]{4})(?:\s*(?:#|x\.?|ext\.?|extension)\s*(\d{1,15}))?$"##
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
// valid
(555)555-5555
1 (555) 555-5555
1 (555)-555-5555
555-555-5555
+1-555-532-3455
1-555-532-3455
1-555-532-3455 ext 4
1 (555) 555-5555 extension 123456789123456
// invalid
555-5555
1234567890
555--555-5555
555-555--5555
1234567
((555))555-5555
invalidphone
+91 (123) 456-7890
123.456.7890
1 (555) 555-5555 extension 0123456789012345
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression