import Foundation
let pattern = #"^((?=[6-9](?<1>){6}|)(?=[3-59](?<1>){3}|)(?=[258](?<1>){2}|)(?=[147](?<1>)|).)+$(?<!(?=(?<-1>.)+(?(1)^))\11(?=((?<=(?=(?=((?<-2>)(?=.*$((?<-2>\2)(?<3>)|){9}).)+(?(2)^))(?>(?<-1>)(.)(?<=((?<5-1>\1)|){9}^.*))*(?<2>.(?<=((?<5>)(?<-1>\1)|){9}((?<-1>\1){10}|())((?<2-1>)(?<-3>\3)|){9}(?<-9>(?<-1>))?(?<1>){10}(?<-3>)(?<-1>)(?<5>^.*)))+$(?!\9)(?(3)^)(?<=(?<-5>(?=(?<1>(?=.*$\5)|.)).)*){10}(\12)?()|){9}^.*).)*)(?<-13>){2}\13(?<-13>)^(?<-14>(?(14)|((?<2>(.)?))){10}(?<-15>))+(?<15>)(.)*|^1)"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
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9971
9973
9977
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression