import Foundation
let pattern = #"(\d{1}\.\d{5,8}|0)\s"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"0.1766155 0.1658146 0.3464225 0.258326 1.040629 0.3123467 0.7877846 0.1264636 0.1854926 2.235324 0 0.3128409 0.5384811 0.2159374 0.1659985 0.2901815 0.08226276 0.1323811 0.1374549 0.04583898 0.1653796 0.02095086 0.1465107 "#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression