re = /[a-zA-Z.0-9\n!)(]*(\s[&|]\s)/
str = 'permission.test1 & permission.test2
permission.test1 | permission.test2
permission.test1 | !permission.test2
permission.test1 | (permission.test2 & permission.test3)'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html