import Foundation
let pattern = ##"(?!.*\.{2})^(?![^@]{11})([a-z\d!#$%&'*+\-\/=?^_`{|}~\u00A0]+(\.[a-z\d!#$%&'*+\-\/=?^_`{|}~\u00A0]+)*|"((([ \t]*\r\n)?[ \t]+)?([\x01-\x08\x0b\x0c\x0e-\x1f\x7f\x21\x23-\x5b\x5d-\x7e\u00A0]|\\[\x01-\x09\x0b\x0c\x0d-\x7f\u00A0]))*(([ \t]*\r\n)?[ \t]+)?")@(([a-z\d\u00A0]|[a-z\d\u00A0][a-z\d\-._~\u00A0]*[a-z\d\u00A0])\.)+([a-z\u00A0]|[a-z\u00A0][a-z\d\-._~\u00A0]*[a-z\u00A0])\.?$"##
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
abc@google.com
abcdefghij@google.com
abcdefghijk@google.com
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression