import Foundation
let pattern = #""(\d+)"(?=[^{]*})"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"i:0;s:2:"34";i:1;s:2:"35";a:29:{i:0;s:2:"34";i:1;s:2:"35";i:2;s:2:"37";i:3;s:2:"36";i:4;s:2:"38";i:5;s:2:"41";i:6;s:2:"33";i:7;s:2:"17";i:8;s:2:"20";i:9;s:2:"18";i:10;s:2:"19";i:11;s:2:"22";i:12;s:2:"23";i:13;s:2:"16";i:14;s:2:"21";i:15;s:2:"43";i:16;s:2:"70";i:17;s:2:"91";i:18;s:2:"50";i:19;s:2:"48";i:20;s:2:"49";i:21;s:2:"53";i:22;s:2:"47";i:23;s:2:"46";i:24;s:2:"44";i:25;s:3:"106";i:26;s:3:"121";i:27;s:2:"95";i:28;s:2:"86";};i:0;s:2:"34";i:1;s:2:"35";"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression