# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"pam\.username%([A-Za-z0-9]+)@|\s\(([0-9]+)\)"
test_str = ("Sep 11 03:02:00 (1568505720.145620) danted[10402]: info: pass(2): tcp/connect -: pam.username%MyUsername@46.111.111.250.48198 123.12.12.112.1080 -> 123.12.12.112.48198 111.123.123.147.443 (319721)\n"
"Sep 11 03:02:00 (1568505720.147471) danted[10402]: info: pass(2): tcp/connect -: pam.username%MyUsername@46.111.111.250.37449 123.12.12.112.1080 -> 123.12.12.112.37449 123.123.123.211.443 (312)\n"
"Sep 11 03:02:00 (1568505720.148240) danted[10402]: info: pass(2): tcp/connect -: 111.123.123.147.443 123.12.12.112.48198 -> 123.12.12.112.1080 pam.username%MyUsername@46.111.111.250.48198 (723)\n"
"Sep 11 03:02:00 (1568505720.154784) danted[10402]: info: pass(2): tcp/connect -: 123.123.123.211.443 123.12.12.112.37449 -> 123.12.12.112.1080 pam.username%MyUsername@46.111.111.250.37449 (8831)")
subst = ""
# You can manually specify the number of replacements by changing the 4th argument
result = re.sub(regex, subst, test_str, 0, re.MULTILINE)
if result:
print (result)
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html