import Foundation
let pattern = ##"^(\#[\da-f]{3}|\#[\da-f]{6}|rgba\(((\d{1,2}|1\d\d|2([0-4]\d|5[0-5]))\s*,\s*){2}((\d{1,2}|1\d\d|2([0-4]\d|5[0-5]))\s*)(,\s*(0\.\d+|1))\)|hsla\(\s*((\d{1,2}|[1-2]\d{2}|3([0-5]\d|60)))\s*,\s*((\d{1,2}|100)\s*%)\s*,\s*((\d{1,2}|100)\s*%)(,\s*(0\.\d+|1))\)|rgb\(((\d{1,2}|1\d\d|2([0-4]\d|5[0-5]))\s*,\s*){2}((\d{1,2}|1\d\d|2([0-4]\d|5[0-5]))\s*)\)|hsl\(\s*((\d{1,2}|[1-2]\d{2}|3([0-5]\d|60)))\s*,\s*((\d{1,2}|100)\s*%)\s*,\s*((\d{1,2}|100)\s*%)\))$"##
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"rgb(234, 160, 160)"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression