import Foundation
let pattern = ##"(?<=\s)(?!\S*[#*])(?!\S*level[0-9])\S+"##
let regex = try! NSRegularExpression(pattern: pattern)
let testString = ##"""
How to write regex which find word (without whitespace) that doesn't contain some chars (like * or #) and sentence also (like level10 or level2 - it should be also regex - level[0-9]+). It will be simple for chars excluded ([^\\s^#^*]+) but how to exclude this 'level' example too ?
I want to exclude chars AND level with number.
Examples:
weesdlevel3fv - shouldn't match because of 'level3'
we3rlevelw4erw - should match - there is level without number
dfs3leveldfvws#3vd - shouldn't match - level is good, but '#' char appeared
level4#level levelw4_level - threat as two words because of whitespaces - only second one should match - no levels with number and no restricted chars like '#' or '*'
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let substitutionString = #""#
let result = regex.stringByReplacingMatches(in: testString, range: stringRange, withTemplate: substitutionString)
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression