re = /[8,9]/m
str = 'I have a regex that matches (8/10) or (9/10) or (10/10) which is good but it also matches (0/10) '
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html