re = /^([12]\d)?(\d\d)[\.\/\-](0?[1-9]|1[012])[\.\/\-](0?[1-9]|[12]\d|3[01])\s([01]?[0-9]|2[0-3]):[0-5][0-9]$/
str = '2013.11.04 11:50'
# Print the match result
str.match(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html