import Foundation
let pattern = #"([A-Z][a-z]+(\s[A-Z][a-z]+)*)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
127.0.0.1 Amigo 30.08.2012 16:08:13 LOGIN OK
192.168.100.2 Vasya Pupkin 30.08.2012 16:08:40 DONE_TASK 15 OK
146.34.15.5 Eduard Petrovich Morozko 13.09.2013 5:04:50 DOWNLOAD_PLUGIN OK
127.0.0.1 Eduard Petrovich Morozko 11.12.2013 10:11:12 WRITE_MESSAGE FAILED
146.34.15.5 Eduard Petrovich Morozko 12.12.2013 21:56:30 WRITE_MESSAGE OK
146.34.15.5 Eduard Petrovich Morozko 03.01.2014 03:45:23 LOGIN OK
192.168.100.2 Vasya Pupkin 30.01.2014 12:56:22 SOLVE_TASK 18 ERROR
127.0.0.1 Vasya Pupkin 14.11.2015 07:08:01 WRITE_MESSAGE OK
192.168.100.2 Vasya Pupkin 19.03.2016 00:00:00 SOLVE_TASK 1 OK
146.34.15.5 Eduard Petrovich Morozko 05.01.2021 20:22:55 DONE_TASK 48 FAILED
127.0.0.1 Vasya Pupkin 14.10.2021 11:38:21 LOGIN OK
12.12.12.12 Amigo 21.10.2021 19:45:25 SOLVE_TASK 18 OK
120.120.120.122 Amigo 29.2.2028 5:4:7 SOLVE_TASK 18 OK
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression