re = /\b(?:0?[1-9]|1[012])[- \/.](?:0?[1-9]|[12][0-9]|3[01])[- \/.](?:19|20)\d\d\b/m
str = '03/04/1991
3/04/1991
03/4/1991'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html