re = /(\d+)\s\(\s(\d+)\s\)|(\d+)(?=\s\(\s(?:\d+\s\(\s\d+\s\)\s)+(\d+))/
str = '3 ( 16 ) 23 ( 24 ( 40 ) 50 ( 66 ) 76 ) 83 ( 88 ( 104 ) 127 )'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html