Regular Expressions 101

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An explanation of your regex will be automatically generated as you type.
Detailed match information will be displayed here automatically.
  • All Tokens
  • Common Tokens
  • General Tokens
  • Anchors
  • Meta Sequences
  • Quantifiers
  • Group Constructs
  • Character Classes
  • Flags/Modifiers
  • Substitution
  • A single character of: a, b or c
    [abc]
  • A character except: a, b or c
    [^abc]
  • A character in the range: a-z
    [a-z]
  • A character not in the range: a-z
    [^a-z]
  • A character in the range: a-z or A-Z
    [a-zA-Z]
  • Any single character
    .
  • Alternate - match either a or b
    a|b
  • Any whitespace character
    \s
  • Any non-whitespace character
    \S
  • Any digit
    \d
  • Any non-digit
    \D
  • Any word character
    \w
  • Any non-word character
    \W
  • Non-capturing group
    (?:...)
  • Capturing group
    (...)
  • Zero or one of a
    a?
  • Zero or more of a
    a*
  • One or more of a
    a+
  • Exactly 3 of a
    a{3}
  • 3 or more of a
    a{3,}
  • Between 3 and 6 of a
    a{3,6}
  • Start of string
    ^
  • End of string
    $
  • A word boundary
    \b
  • Non-word boundary
    \B

Regular Expression
Processing...

Test String

Substitution
Processing...

Code Generator

Language

Generated Code

import re regex = re.compile(r"\s*((?:\b(?:[djms]rs?|flam|liq|qr|st)\.|\b(?:[a-z]\.){2,}|\.\d[\d.]*|\.(?:com|net|org)\b|[^.?!])+(?:[.?!]+|$))", flags=re.MULTILINE | re.IGNORECASE) test_str = ("Section 2.1. Classification of Subsatnces \n\n" "Mr. and Mrs. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid a lot for it. Did he mind? Dr. Adam Jones Jr. thinks he didn't. In any case, this isn't true... Well, with a probability of .9 it isn't.However, this line wont do it. Qr. Test for Website.COM and Labs.ORG looks good.Creatively not working. t and finished. 9 to start. Highly Flammable Liquid Flam. H223 Liq. H334. \n" "St. Bernard Dog was present.\n" "The MW of gold is 100.1. Solubility is 40mg/L.") subst = "$1\\n" result = regex.sub(subst, test_str) if result: print(result)

Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html