using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @"^((\d{2}(([02468][048])|([13579][26]))[\-\/\s]?((((0?[13578])|(1[02]))[\-\/\s]?((0?[1-9])|([1-2][0-9])|(3[01])))|(((0?[469])|(11))[\-\/\s]?((0?[1-9])|([1-2][0-9])|(30)))|(0?2[\-\/\s]?((0?[1-9])|([1-2][0-9])))))|(\d{2}(([02468][1235679])|([13579][01345789]))[\-\/\s]?((((0?[13578])|(1[02]))[\-\/\s]?((0?[1-9])|([1-2][0-9])|(3[01])))|(((0?[469])|(11))[\-\/\s]?((0?[1-9])|([1-2][0-9])|(30)))|(0?2[\-\/\s]?((0?[1-9])|(1[0-9])|(2[0-8]))))))(\s(((0?[1-9])|(1[0-9])|(2[0-3]))\:([0-5][0-9])((\s)|(\:([0-5][0-9])))?))?$";
string input = @"16/10/1991
16-10-1991
16.10.1991
1991/16/10
1991-16-10
1991.16.10
10/16/1991
10-16-1991
10.16.1991
1991-10-16
1991/10/16
2016-2-29
2020-2-29
2024-2-29
2028-2-29
2032-2-29
2036-2-29
2040-2-29
5304-2-29
1991.10.16
91-10-16
91/10/16
91.10.16
01/01/2000
31/01/2000
32/01/2000
01/1/2000
01/1/01
29/02/2000
28/02/2001
29/02/2003
30/04/2000
31/04/2000
31/07/2000
31/08/2000
31/09/2000
01/12/2000
01/15/2000
";
RegexOptions options = RegexOptions.Multiline;
foreach (Match m in Regex.Matches(input, pattern, options))
{
Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index);
}
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for C#, please visit: https://msdn.microsoft.com/en-us/library/system.text.regularexpressions.regex(v=vs.110).aspx