import Foundation
let pattern = ##"(\d{3})@.*?@(\d{3})-(\d{3})-(\d{4})\s+(\d{2}:\d{2}:\d{2})\s(\d{8})@(.*?)@(.*?)([WV].{3})@(.*?)@(.*?)LEC\s(.*?)@(.{29})([A-Z]{2})@(.*?)@.*?ESN(.*?)@P#(.{12}).*?ALT#(\d{3})-(\d{3})-(\d{4})@X(.{11}).*?Y(.{11})(.*?)@(.*?)@(.*?)@(.*?)(.*?)@(.*?)@"##
let regex = try! NSRegularExpression(pattern: pattern)
let testString = ##"""
_201@ @815-440-0499 14:12:30 01162018@VERIZON @936A WPH2@STONY POINT RD @ LEC VERIZ@DIXON IL@W SECTOR @ ESN 199@P#815-440-0499 ALT#815-511-7655@X-089.482548 Y+041.840840 CF90 @UNC00025 Z ZUNC @WIRELESS 911 CALL @WIRELESS 911 CALL @WIRELESS 911 CALL @_
204@ @319-430-1670 11:28:30 01162018@VERIZON WIRELESS @ WPH1@LINCOLN HWY @ LEC VERIZ@DIXON IL@NE SECTOR @ ESN 199@P#319-430-1670 ALT#815-511-7657@X-089.488534 Y+041.837557 CF0 @UNC00000 Z ZUNC @WIRELESS 911 CALL @WIRELESS 911 CALL @WIRELESS 911 CALL @_
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression