const regex = /(?:(?:ht|f)tp(?:s?)\:\/\/|~\/|\/)?(?:\w+:\w+@)?((?:(?:[-\w\d{1-3}]+\.)+(?:com|org|net|gov|mil|biz|info|mobi|name|aero|jobs|edu|co\.uk|ac\.uk|it|fr|tv|museum|asia|local|travel|[a-z]{2}))|((\b25[0-5]\b|\b[2][0-4][0-9]\b|\b[0-1]?[0-9]?[0-9]\b)(\.(\b25[0-5]\b|\b[2][0-4][0-9]\b|\b[0-1]?[0-9]?[0-9]\b)){3}))(?::[\d]{1,5})?(?:(?:(?:\/(?:[-\w~!$+|.,=]|%[a-f\d]{2})+)+|\/)+|\?|#)?(?:(?:\?(?:[-\w~!$+|.,*:]|%[a-f\d{2}])+=?(?:[-\w~!$+|.,*:=]|%[a-f\d]{2})*)(?:&(?:[-\w~!$+|.,*:]|%[a-f\d{2}])+=?(?:[-\w~!$+|.,*:=]|%[a-f\d]{2})*)*)*(?:#(?:[-\w~!$ |\/.,*:;=]|%[a-f\d]{2})*)?/ig;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('(?:(?:ht|f)tp(?:s?)\\:\\\/\\\/|~\\\/|\\\/)?(?:\\w+:\\w+@)?((?:(?:[-\\w\\d{1-3}]+\\.)+(?:com|org|net|gov|mil|biz|info|mobi|name|aero|jobs|edu|co\\.uk|ac\\.uk|it|fr|tv|museum|asia|local|travel|[a-z]{2}))|((\\b25[0-5]\\b|\\b[2][0-4][0-9]\\b|\\b[0-1]?[0-9]?[0-9]\\b)(\\.(\\b25[0-5]\\b|\\b[2][0-4][0-9]\\b|\\b[0-1]?[0-9]?[0-9]\\b)){3}))(?::[\\d]{1,5})?(?:(?:(?:\\\/(?:[-\\w~!$+|.,=]|%[a-f\\d]{2})+)+|\\\/)+|\\?|#)?(?:(?:\\?(?:[-\\w~!$+|.,*:]|%[a-f\\d{2}])+=?(?:[-\\w~!$+|.,*:=]|%[a-f\\d]{2})*)(?:&(?:[-\\w~!$+|.,*:]|%[a-f\\d{2}])+=?(?:[-\\w~!$+|.,*:=]|%[a-f\\d]{2})*)*)*(?:#(?:[-\\w~!$ |\\\/.,*:;=]|%[a-f\\d]{2})*)?', 'ig')
const str = `Hey there StackOverflow.com, how's stuff.co going? This.xyz is not valid.`;
const subst = ``;
// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);
console.log('Substitution result: ', result);
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions