using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @"(\d)(-\d*\.)";
string substitution = @"\1 \2";
string input = @"1 0.00000E+00-7.52896E-04 0.00000E+00 0.00000E+00 0.00000E+00 0.00000E+00 0.00000E+00 0.00000E+00 0.00000E+00 0.00000E+00 1.00247E-01 0.00000E+00
9 2.57945E+00-9.98377E-04 0.00000E+00 1.80923E+02 0.00000E+00 0.00000E+00 1.08995E+03 0.00000E+00 0.00000E+00 1.00795E+01 1.00002E-01 0.00000E+00
18 2.37285E+00-2.20000E-01 0.00000E+00 1.81079E+02-5.53001E+00 0.00000E+00 1.30827E+03 2.01207E+03 0.00000E+00 9.87285E+00 8.64615E-01 0.00000E+00";
Regex regex = new Regex(pattern);
string result = regex.Replace(input, substitution);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for C#, please visit: https://msdn.microsoft.com/en-us/library/system.text.regularexpressions.regex(v=vs.110).aspx