const regex = new RegExp('(\\d)(-\\d*\\.)', 'g')
const str = `1 0.00000E+00-7.52896E-04 0.00000E+00 0.00000E+00 0.00000E+00 0.00000E+00 0.00000E+00 0.00000E+00 0.00000E+00 0.00000E+00 1.00247E-01 0.00000E+00
9 2.57945E+00-9.98377E-04 0.00000E+00 1.80923E+02 0.00000E+00 0.00000E+00 1.08995E+03 0.00000E+00 0.00000E+00 1.00795E+01 1.00002E-01 0.00000E+00
18 2.37285E+00-2.20000E-01 0.00000E+00 1.81079E+02-5.53001E+00 0.00000E+00 1.30827E+03 2.01207E+03 0.00000E+00 9.87285E+00 8.64615E-01 0.00000E+00`;
const subst = `\1 \2`;
// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);
console.log('Substitution result: ', result);
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions