import Foundation
// WARNING: You included a flag that Swift doesn't support: u
// When this flag is set, it makes the pattern and subject strings to be treated as unicode.
// Swift already treats the pattern and subject strings as unicode by default, so including this flag is redundant.
let pattern = #"44999"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
84951234567
+74951234567
8-495-1-234-567
8 (8122) 56-56-56
8-911-1234567
8 (911) 12 345 67
8-911 12 345 67
8 (911) - 123 - 45 - 67
+ 7 999 123 4567
8 ( 999 ) 1234567
8 999 123 4567
// выше - правильные, ниже - неправильные:
02
84951234567 позвать люсю
849512345
849512345678
8 (409) 123-123-123
7900123467
5005005001
8888-8888-88
84951a234567
8495123456a
+1 234 5678901
+8 234 5678901
7 234 5678901
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
if let firstMatch = regex.firstMatch(in: testString, range: stringRange) {
let result: [String] = (1 ..< firstMatch.numberOfRanges).map { (testString as NSString).substring(with: firstMatch.range(at: $0)) }
print(result)
} else {
print("No matches were found.")
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression