import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String[] args) {
final String regex = "’s/\\_[0-9]{14}_/\\_/’\n";
final String string = "10.209.85.14_20160831010034_show_run.txt\n"
+ "10.209.85.17_20160831010057_show_run.txt\n"
+ "10.209.85.18_20160831010104_show_run.txt\n"
+ "10.209.85.19_20160831010112_show_run.txt\n"
+ "10.209.85.20_20160831010001_show_run.txt\n"
+ "10.209.85.226_20160831010224_show_run.txt\n"
+ "10.209.85.227_20160831010228_show_run.txt\n"
+ "10.209.85.228_20160831010303_show_run.txt\n"
+ "10.217.76.10_20160831010159_show_run.txt\n"
+ "10.217.76.11_20160831010159_show_run.txt\n"
+ "10.217.76.12_20160831010206_show_run.txt\n"
+ "10.217.76.13_20160831010212_show_run.txt\n"
+ "10.217.76.14_20160831010219_show_run.txt\n"
+ "10.217.76.7_20160831010119_show_run.txt\n"
+ "10.217.76.9_20160831010122_show_run.txt\n"
+ "10.217.77.226_20160831010309_show_run.txt\n"
+ "10.217.77.227_20160831010342_show_run.txt\n"
+ "10.217.77.228_20160831010417_show_run.txt\n";
final String subst = "_";
final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
final Matcher matcher = pattern.matcher(string);
// The substituted value will be contained in the result variable
final String result = matcher.replaceAll(subst);
System.out.println("Substitution result: " + result);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Java, please visit: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html