# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"Version\s(\d+\.\d+(?:\([^()+]\)[A-Z]\d|\.\d{2}[a-z]))"
test_str = ("String 1-Cisco IOS Software, C3900 Software (C3900-UNIVERSALK9-M), Version 15.4(3)M3, RELEASE SOFTWARE (fc2)\n"
"ROM: System Bootstrap, Version 15.0(1r)M16, RELEASE SOFTWARE (fc1)\n\n"
"String2-Cisco IOS XE Software, Version 16.05.01b\n"
"Cisco IOS Software [Everest], ISR Software (X86_64_LINUX_IOSD-UNIVERSALK9-M), Version 16.5.1b, RELEASE SOFTWARE (fc1)\n"
"licensed under the GNU General Public License (\"GPL\") Version 2.0. The\n"
"software code licensed under GPL Version 2.0 is free software that comes\n"
"GPL code under the terms of GPL Version 2.0. For more details, see the")
matches = re.finditer(regex, test_str, re.MULTILINE)
for matchNum, match in enumerate(matches, start=1):
print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))
for groupNum in range(0, len(match.groups())):
groupNum = groupNum + 1
print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html