import Foundation
let pattern = #"^[\w.]+=\$(?:\d|1[012])(?:\|[\w.]+=\$(?:\d|1[012]))*$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
Valid Values:
ABC=$2|CDE=$1|Msg=$4|Ph.No=$3|TIME=$5
ABC=$2|CDE=$1|Msg123=$4|Ph.No=$3|TIME_23=$5
abc=$2|123=$1|cfg=$4|Ph.No=$3
ABC=$12|CDE=$1|Msg=$12|Ph.No=$11|TIME=$5
ABC=$12|CDE=$6|Msg123=$9|Ph.No=$3|TIME_23=$10
Invalid Values:
ABC=$2CDE=$1Msg=$4
ABC=2|CDE=1|Msg123=$4|Ph.No=$3|TIME_23=$5
abc$2|123$1|cfg$4|Ph.No=$3
Msg123=$ |Ph.No=$ |TIME_23=5
abcdefgh|1234|eghjik
Msg123=$*|Ph.No=$()|TIME_23=$5
Msg123=$a|Ph.No=$b|TIME_23=$p
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression