import Foundation
let pattern = #"^(?!\b(\d)\1+\b)(?!123456789|002281852|042103580|062360749|078051120|095073645|128036045|135016629|141186941|165167999|165187999|165207999|165227999|165247999|189092294|212097694|212099999|306302348|308125070|468288779|549241889)(?!000|666|9\d{2})\d{2}(?!00)\d{2}(?!0{4})\d{4}$"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"12121234"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
if let firstMatch = regex.firstMatch(in: testString, range: stringRange) {
let result: [String] = (1 ..< firstMatch.numberOfRanges).map { (testString as NSString).substring(with: firstMatch.range(at: $0)) }
print(result)
} else {
print("No matches were found.")
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression