import Foundation
let pattern = #"oz(3[4-9]|[4-9][0-9]|[1-9][0-9]{2}|[12][0-9]{3}|3[0-8][0-9]{2}|39[0-7][0-9]|398[0-2])"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"oz31 oz32 oz33 oz34 oz35 oz55 oz100 oz123 oz999 oz1000 oz2000 oz3000 oz3981 oz3982 oz3983"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression