import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String[] args) {
final String regex = "[^\\:]+:([\\d\\s]+\\s\\s).*";
final String string = "0000000: 01010000 01001011 00000011 00000100 00010100 00000011 PK.... \n"
+ "0000006: 00000000 00000000 00001000 00000000 01000000 10001101 ....@. \n"
+ "000000c: 00101001 01000110 10011111 00101100 00000001 11100100 )F.,.. \n"
+ "0000012: 01111100 00101011 00000000 00000000 10111110 11010111 |+.... \n"
+ "0000018: 00000010 00000000 00001101 00000000 00000000 00000000 ...... \n"
+ "000001e: 01110000 01100001 01101110 01100100 01100001 01011111 panda_ \n"
+ "0000024: 01100010 01101001 01101110 00101110 01110100 01111000 bin.tx \n"
+ "000002a: 01110100 10101100 10011010 01001001 10101110 10011011 t..I.. \n"
+ "0000030: 01010000 00010000 01000101 11100111 01011001 10000101 P.E.Y. ";
final String subst = "$1\\n";
final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
final Matcher matcher = pattern.matcher(string);
// The substituted value will be contained in the result variable
final String result = matcher.replaceAll(subst);
System.out.println("Substitution result: " + result);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Java, please visit: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html