re = /^(((25[0-5])|(2[0-4]\d)|(1\d{2})|(\d{1,2}))\.){3}(((25[0-5])|(2[0-4]\d)|(1\d{2})|(\d{1,2})))$/m
str = '1.1.1.1
254.2.2.2.
255.1.1.255
256.1.1.256
012.111.111.111
12.12.12.12a
1q.1.1.1
1.1q.1.1
1.1.1q.1
1.1.1.1q
abcde254.2.2.2'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html